In short: CBSE Class 10 Science Sample Paper 2027 has 39 questions across 5 sections — 80 marks in 3 hours. Section A has 20 MCQs, Section B has 6 questions (2 marks), Section C has 7 questions (3 marks), Section D has 3 questions (5 marks), and Section E has 3 case-based questions (4 marks). Physics, Chemistry, and Biology are equally weighted. This guide covers complete solutions, diagrams, and scoring strategies.
Paper Pattern 2027
Exam Structure
| Aspect | Details |
|---|---|
| Total Marks | 80 (Theory) + 20 (Internal Assessment) = 100 |
| Duration | 3 hours |
| Total Questions | 39 |
| Sections | 5 (A, B, C, D, E) |
| Internal Choice | Available in Sections B, C, D, E |
Section-wise Breakdown
| Section | Question Type | Questions | Marks per Q | Total Marks |
|---|---|---|---|---|
| A | MCQs | 20 | 1 | 20 |
| B | Very Short Answer | 6 | 2 | 12 |
| C | Short Answer | 7 | 3 | 21 |
| D | Long Answer | 3 | 5 | 15 |
| E | Case-Based | 3 | 4 | 12 |
| Total | 39 | 80 |
Chapter-wise Weightage 2027
| Unit | Chapters | Marks | Percentage |
|---|---|---|---|
| Chemical Substances | Ch 1-5 (Reactions, Acids, Metals, Carbon, Periodic Table) | 25 | 31% |
| World of Living | Ch 6-9 (Life Processes, Control, Reproduction, Heredity) | 25 | 31% |
| Natural Phenomena | Ch 10-11 (Light, Human Eye) | 12 | 15% |
| Effects of Current | Ch 12-13 (Electricity, Magnetic Effects) | 13 | 16% |
| Natural Resources | Ch 14-15 (Sources of Energy, Environment) | 5 | 7% |
| Total | 80 | 100% |
High-Weightage Chapters
| Chapter | Marks | Priority |
|---|---|---|
| Chemical Reactions and Equations | 8-10 | 🔴 Very High |
| Life Processes | 8-10 | 🔴 Very High |
| Electricity | 7-8 | 🔴 Very High |
| Light — Reflection and Refraction | 6-7 | 🔴 Very High |
| Heredity and Evolution | 5-6 | 🟠 High |
| Carbon and its Compounds | 5-6 | 🟠 High |
| Acids, Bases and Salts | 4-5 | 🟠 High |
Section A — MCQs (20 × 1 = 20 Marks)
Chemistry MCQs
Q1. A solution reacts with crushed egg shells to give a gas that turns lime water milky. The solution contains:
- (a) NaCl
- (b) HCl
- (c) LiCl
- (d) KCl
Solution: Egg shells contain CaCO₃. When acid reacts with carbonate, CO₂ is released which turns lime water milky. CaCO₃ + 2HCl → CaCl₂ + H₂O + CO₂↑
Answer: (b) HCl
Q2. What happens when dilute hydrochloric acid is added to iron filings?
- (a) Hydrogen gas and iron chloride are produced
- (b) Chlorine gas and iron hydroxide are produced
- (c) No reaction takes place
- (d) Iron salt and water are produced
Solution: Fe + 2HCl → FeCl₂ + H₂↑ Iron displaces hydrogen from acid (more reactive than hydrogen).
Answer: (a) Hydrogen gas and iron chloride are produced
Q3. Which of the following is NOT a characteristic of carbon compounds?
- (a) They have low melting and boiling points
- (b) They are good conductors of electricity
- (c) They show isomerism
- (d) They undergo combustion reactions
Solution: Carbon compounds are covalent compounds with weak intermolecular forces. They are poor conductors of electricity.
Answer: (b) They are good conductors of electricity
Biology MCQs
Q4. The blood vessel that carries blood from the lungs to the heart is:
- (a) Pulmonary artery
- (b) Pulmonary vein
- (c) Aorta
- (d) Vena cava
Solution: Pulmonary vein carries oxygenated blood from lungs to left atrium of heart. Pulmonary artery carries deoxygenated blood from heart to lungs.
Answer: (b) Pulmonary vein
Q5. In human females, the fertilization of egg by sperm takes place in:
- (a) Uterus
- (b) Ovary
- (c) Fallopian tube (Oviduct)
- (d) Vagina
Solution: Fertilization occurs in the fallopian tube (oviduct). The fertilized egg then travels to the uterus for implantation.
Answer: (c) Fallopian tube (Oviduct)
Q6. Which of the following is NOT a function of stomata?
- (a) Exchange of gases
- (b) Transpiration
- (c) Photosynthesis
- (d) Absorption of water
Solution: Stomata allow gas exchange and transpiration. Water absorption is done by roots, not stomata.
Answer: (d) Absorption of water
Physics MCQs
Q7. A concave mirror produces a real, inverted image of the same size as the object. The object is placed at:
- (a) Focus
- (b) Centre of curvature
- (c) Between focus and centre of curvature
- (d) Beyond centre of curvature
Solution: When object is at C (centre of curvature), image is at C, real, inverted, and same size.
Answer: (b) Centre of curvature
Q8. The SI unit of electric current is:
- (a) Volt
- (b) Ohm
- (c) Ampere
- (d) Watt
Solution: Electric current is measured in Ampere (A). 1 Ampere = 1 Coulomb/second
Answer: (c) Ampere
Q9. Two resistors of 4Ω and 6Ω are connected in parallel. The equivalent resistance is:
- (a) 10Ω
- (b) 2.4Ω
- (c) 24Ω
- (d) 0.4Ω
Solution: For parallel: 1/Req = 1/R₁ + 1/R₂ 1/Req = 1/4 + 1/6 = (3+2)/12 = 5/12 Req = 12/5 = 2.4Ω
Answer: (b) 2.4Ω
Q10. The phenomenon of electromagnetic induction was discovered by:
- (a) Oersted
- (b) Faraday
- (c) Ampere
- (d) Fleming
Solution: Michael Faraday discovered electromagnetic induction in 1831.
Answer: (b) Faraday
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Section B — Very Short Answer (6 × 2 = 12 Marks)
Q21. Why does the colour of copper sulphate solution change when an iron nail is dipped in it?
Solution: Iron is more reactive than copper. Iron displaces copper from copper sulphate solution.
Fe + CuSO₄ → FeSO₄ + Cu
- Blue colour of CuSO₄ fades (Cu²⁺ ions removed)
- Green colour of FeSO₄ appears (Fe²⁺ ions formed)
- Reddish-brown copper deposits on iron nail
Answer: Iron displaces copper from the solution (displacement reaction), changing blue CuSO₄ to green FeSO₄.
Q22. What is the role of acid in our stomach? What happens when there is excess acid in the stomach?
Solution: Role of HCl in stomach:
- Kills bacteria in food
- Activates pepsinogen to pepsin (protein-digesting enzyme)
- Provides acidic medium (pH 1.5-2) for pepsin action
Excess acid causes:
- Acidity/heartburn
- Indigestion
- Ulcers (in severe cases)
Remedy: Antacids (milk of magnesia, baking soda) neutralize excess acid.
Q23. Draw a diagram of human brain and label: (i) Cerebrum (ii) Cerebellum
Solution:
[Diagram of Human Brain - Side View]
_______________
/ \
/ CEREBRUM \ ← (i) Largest part, thinking, memory
| |
| |
\ /
\_______________/
|
CEREBELLUM ← (ii) Balance, posture, coordination
|
MEDULLA
|
SPINAL CORD
Labels:
- (i) Cerebrum — Controls thinking, memory, intelligence, voluntary actions
- (ii) Cerebellum — Controls balance, posture, coordination of movements
Q24. An object is placed at a distance of 30 cm from a concave mirror of focal length 15 cm. Find the position and nature of the image.
Solution: Given: u = -30 cm, f = -15 cm (concave mirror)
Using mirror formula: 1/v + 1/u = 1/f 1/v + 1/(-30) = 1/(-15) 1/v = -1/15 + 1/30 1/v = (-2 + 1)/30 = -1/30 v = -30 cm
Position: 30 cm in front of mirror (same side as object) Nature: Real, inverted, same size (since v = u)
Section C — Short Answer (7 × 3 = 21 Marks)
Q27. What is a homologous series? Write any two characteristics. Give an example.
Solution: Definition: A homologous series is a group of organic compounds with the same functional group and similar chemical properties, where successive members differ by -CH₂- unit.
Characteristics:
- Same general formula (e.g., CₙH₂ₙ₊₂ for alkanes)
- Same functional group
- Similar chemical properties
- Gradual change in physical properties (boiling point, melting point increase with molecular mass)
- Successive members differ by -CH₂- (14 u mass difference)
Example: Alkane series
- Methane: CH₄
- Ethane: C₂H₆
- Propane: C₃H₈
- Butane: C₄H₁₀
Q28. Explain the process of nutrition in Amoeba with the help of a diagram.
Solution: Amoeba shows holozoic nutrition through the following steps:
1. Ingestion: Amoeba engulfs food (bacteria, algae) using pseudopodia. Food is enclosed in a food vacuole.
2. Digestion: Digestive enzymes are secreted into the food vacuole. Complex food is broken into simpler substances.
3. Absorption: Digested food is absorbed into the cytoplasm.
4. Assimilation: Absorbed food is used for energy and growth.
5. Egestion: Undigested food is expelled by rupturing the cell membrane.
[Diagram: Nutrition in Amoeba]
Pseudopodia extending
↓
___________
/ \
| Food | ← Food particle being engulfed
| Vacuole |
| (•) | ← Nucleus
\___________/
↓
Food vacuole formed
Q29. Derive the expression for the equivalent resistance when three resistors R₁, R₂, and R₃ are connected in series.
Solution: In series connection:
- Same current (I) flows through all resistors
- Total voltage = Sum of individual voltages
Let V₁, V₂, V₃ be voltages across R₁, R₂, R₃ respectively.
By Ohm's law: V₁ = IR₁, V₂ = IR₂, V₃ = IR₃
Total voltage: V = V₁ + V₂ + V₃ V = IR₁ + IR₂ + IR₃ V = I(R₁ + R₂ + R₃)
If Req is equivalent resistance: V = IReq
Therefore: Req = R₁ + R₂ + R₃
In series, equivalent resistance is the sum of individual resistances.
Section D — Long Answer (3 × 5 = 15 Marks)
Q33. (a) What is meant by refraction of light? State the laws of refraction. (b) A ray of light travelling in air enters obliquely into water. Does the light ray bend towards the normal or away from it? Why?
Solution:
(a) Refraction of Light: The bending of light when it passes from one transparent medium to another is called refraction.
Laws of Refraction (Snell's Law):
First Law: The incident ray, the refracted ray, and the normal to the interface at the point of incidence, all lie in the same plane.
Second Law: The ratio of sine of angle of incidence to the sine of angle of refraction is constant for a given pair of media.
sin i / sin r = constant = n₂₁ (refractive index)
(b) Light bends towards the normal.
Reason:
- Air is optically rarer medium (n = 1.0)
- Water is optically denser medium (n = 1.33)
- When light travels from rarer to denser medium, it slows down
- This causes the light ray to bend towards the normal
[Diagram]
Normal
|
Air |
--------|--------
|\
Water | \ Refracted ray
| \
| (bends towards normal)
Q34. (a) Draw a diagram of the human excretory system and label: (i) Kidney (ii) Ureter (iii) Urinary bladder (iv) Urethra
(b) Explain the process of urine formation in kidneys.
Solution:
(a) Diagram of Human Excretory System:
Right Kidney Left Kidney
___ ___
/ \ / \
| | | |
\___/ \___/
| |
| Ureters |
| ↓ |
|______|_______|
|
Urinary Bladder
( )
|
Urethra
↓
Labels:
- (i) Kidney — Bean-shaped organs that filter blood
- (ii) Ureter — Tubes carrying urine from kidney to bladder
- (iii) Urinary bladder — Stores urine temporarily
- (iv) Urethra — Tube through which urine is expelled
(b) Process of Urine Formation:
Urine formation occurs in nephrons through three steps:
1. Glomerular Filtration (Ultrafiltration):
- Blood enters glomerulus under high pressure
- Small molecules (water, glucose, salts, urea) filter into Bowman's capsule
- Large molecules (proteins, blood cells) remain in blood
- Filtrate formed = 180 L/day
2. Tubular Reabsorption:
- Useful substances reabsorbed in proximal tubule
- Glucose, amino acids, salts, water reabsorbed into blood
- About 99% of filtrate is reabsorbed
3. Tubular Secretion:
- Additional waste (H⁺, K⁺, urea) secreted from blood into tubule
- Maintains blood pH and ionic balance
Final urine: About 1.5-2 L/day, containing urea, excess salts, water.
Q35. (a) What is an electromagnet? How is it different from a permanent magnet? (b) Draw a labelled diagram of an electric motor. State its principle.
Solution:
(a) Electromagnet: An electromagnet is a temporary magnet made by winding an insulated copper wire around a soft iron core and passing electric current through it.
| Electromagnet | Permanent Magnet |
|---|---|
| Temporary magnet | Permanent magnet |
| Magnetic field can be switched on/off | Always magnetic |
| Strength can be varied (by changing current) | Fixed strength |
| Made of soft iron | Made of steel, alnico, etc. |
| Used in cranes, bells, MRI | Used in compasses, speakers |
(b) Electric Motor:
Principle: An electric motor works on the principle that a current-carrying conductor placed in a magnetic field experiences a force (Fleming's Left Hand Rule).
[Diagram of Electric Motor]
N ←――――――――――――→ S
| |
| AB |
_____|______|_____
| ↑ ↓ |
| Coil ABCD |
|_____|______|_____|
| |
Split Ring Commutator
| |
Brushes (B₁, B₂)
|
Battery
Components:
- Rectangular coil ABCD
- Strong permanent magnet (N-S poles)
- Split ring commutator (reverses current direction)
- Carbon brushes (maintain contact)
- Axle (rotation axis)
Working: Current flows through coil → coil experiences force → coil rotates → commutator reverses current → rotation continues.
Section E — Case-Based Questions (3 × 4 = 12 Marks)
Case Study 1: Electricity in Daily Life
A household uses various electrical appliances. The following table shows the power rating and usage time of some appliances:
| Appliance | Power (W) | Usage (hours/day) |
|---|---|---|
| LED Bulb | 10 | 6 |
| Fan | 75 | 10 |
| TV | 100 | 4 |
| Refrigerator | 150 | 24 |
Q36.
(i) Calculate the energy consumed by the fan in one day.
Solution: Energy = Power × Time Energy = 75 W × 10 h = 750 Wh = 0.75 kWh
Answer: 0.75 kWh or 750 Wh
(ii) Which appliance consumes maximum energy in a day?
Solution:
- LED Bulb: 10 × 6 = 60 Wh
- Fan: 75 × 10 = 750 Wh
- TV: 100 × 4 = 400 Wh
- Refrigerator: 150 × 24 = 3600 Wh
Answer: Refrigerator (3600 Wh = 3.6 kWh)
(iii) If electricity costs ₹5 per unit (kWh), calculate the monthly bill for the refrigerator (30 days).
Solution: Daily consumption = 3.6 kWh Monthly consumption = 3.6 × 30 = 108 kWh Monthly bill = 108 × ₹5 = ₹540
Answer: ₹540
Case Study 2: Human Reproduction
The human reproductive system ensures continuation of species. The diagram shows the female reproductive system.
Q37.
(i) Name the organ where fertilization takes place.
Answer: Fallopian tube (Oviduct)
(ii) What is the function of the placenta?
Solution: Functions of placenta:
- Provides nutrients (glucose, oxygen) from mother to foetus
- Removes waste (CO₂, urea) from foetus to mother
- Acts as a barrier against pathogens
- Produces hormones (progesterone, estrogen) to maintain pregnancy
Answer: Placenta provides nutrients and oxygen to the foetus and removes waste products.
(iii) Why is it important that the testes are located outside the abdominal cavity?
Solution: Sperm production (spermatogenesis) requires a temperature 2-3°C lower than body temperature. The scrotum, located outside the body, maintains this lower temperature for optimal sperm production.
Answer: Testes need lower temperature (2-3°C below body temperature) for sperm formation.
Case Study 3: Chemical Reactions
When a magnesium ribbon is burnt in air, it produces a white powder with a bright flame.
Q38.
(i) Write the balanced chemical equation for this reaction.
Solution: 2Mg + O₂ → 2MgO
Answer: 2Mg + O₂ → 2MgO
(ii) What type of chemical reaction is this? Give two reasons.
Solution: This is a combination reaction (two substances combine to form one product).
It is also an oxidation reaction (magnesium gains oxygen).
Reasons:
- Two reactants (Mg and O₂) combine to form one product (MgO)
- Magnesium is oxidized (gains oxygen)
- Heat and light are released (exothermic)
(iii) What is the nature of magnesium oxide? How can you test it?
Solution: Magnesium oxide is basic in nature.
Test: Dissolve MgO in water to form Mg(OH)₂. Add red litmus paper — it turns blue (confirms basic nature).
MgO + H₂O → Mg(OH)₂ (Magnesium hydroxide - base)
Marking Scheme Tips
How to Score Full Marks
| Question Type | Marking Pattern | Tips |
|---|---|---|
| MCQs | 1 mark for correct option | Eliminate wrong options first |
| 2-mark | 1 for concept + 1 for application | Write 2 distinct points |
| 3-mark | 1 per point or step | Include diagram if relevant |
| 5-mark | 1 per major point + 1 for diagram | Always draw labeled diagrams |
| Case-based | 1 per sub-part | Read case carefully, answer precisely |
Diagram Marks
| Diagram | Marks | Must Include |
|---|---|---|
| Human heart | 2 | All 4 chambers, major vessels |
| Human brain | 2 | Cerebrum, cerebellum, medulla |
| Nephron | 2 | Glomerulus, tubules, collecting duct |
| Electric motor | 2 | Coil, magnet, commutator, brushes |
| Eye defects | 1-2 | Lens, retina, focal point |
How to Score 90%+ in Science
Subject-wise Strategy
| Subject | Focus Areas | Marks |
|---|---|---|
| Chemistry | Reactions, equations, carbon compounds | 25 |
| Biology | Diagrams, processes, definitions | 25 |
| Physics | Numericals, derivations, ray diagrams | 30 |
Last 30 Days Plan
| Week | Focus |
|---|---|
| Week 1 | Complete NCERT, highlight important diagrams |
| Week 2 | Practice numericals (Physics), reactions (Chemistry) |
| Week 3 | Solve 5 sample papers with timer |
| Week 4 | Revise diagrams, formulas, definitions daily |
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